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5x^2/3=320
We move all terms to the left:
5x^2/3-(320)=0
We multiply all the terms by the denominator
5x^2-320*3=0
We add all the numbers together, and all the variables
5x^2-960=0
a = 5; b = 0; c = -960;
Δ = b2-4ac
Δ = 02-4·5·(-960)
Δ = 19200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{19200}=\sqrt{6400*3}=\sqrt{6400}*\sqrt{3}=80\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80\sqrt{3}}{2*5}=\frac{0-80\sqrt{3}}{10} =-\frac{80\sqrt{3}}{10} =-8\sqrt{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80\sqrt{3}}{2*5}=\frac{0+80\sqrt{3}}{10} =\frac{80\sqrt{3}}{10} =8\sqrt{3} $
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